Question
A wheel has angular acceleration of $3 .0\, rad/sec^2$ and an initial angular speed of $2.00\, rad/sec.$ In a time of $2\, sec$ it has rotated through an angle (in radian) of
${\omega _i} = 2\,rad/\sec $
Time $t = 2 \;sec$
Using, $\theta = {\omega _i}t + \frac{1}{2}\alpha {t^2}$
$\therefore \,\theta = 2 \times 2 + \frac{1}{2} \times 3 \times 4 $$= 4 + 6 = 10\,radian.$
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