MCQ
A wheel has angular acceleration of $3.0\, rad/s^2$ and an initial angular speed of $2.00\, rad/s$. In a time of $2\, s$ it has rotated through an angle (in radian) of
- A$6$
- ✓$10$
- C$12$
- D$4$
${\omega _0} = 2\,rad/s,\,angular\,acceleration,$
$\alpha = 3rad/{s^2},time,\,t = 2s$
From the equation of the angular displacement,
$\theta = {\omega _0}t + \frac{1}{2}\alpha {t^2} = 2 \times 2 + \frac{1}{2} \times 3 \times {\left( 2 \right)^2}$
$ = 4 + 6 = 10\,radians$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.


