MCQ
$A $ will be


- A$\begin{matrix}
C{{H}_{2}}=CH-CH-C{{H}_{3}} \\
\,\,\,\,\,\,\,\,\,| \\
\,\,\,\,\,\,\,\,\,\,\,\,\,OH \\
\end{matrix}$ - ✓

- C

- D







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Reason : Inert gases have stable configuration.
$HCHO\xrightarrow[{dil{H_2}S{O_4}}]{{NaCN}}A\xrightarrow[{\operatorname{P} t}]{{{H_2}}}B$ The product $(B)$ is
