A wire has a resistance of $6 \,\Omega$. It is cut into two parts and both half values are connected in parallel. The new resistance is ................ $\Omega$
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Given $R = 6\,\Omega $.
When resistor is cut into two equal parts and connected in parallel, then
${R_{eq}} = \frac{{R/2}}{2}$ $ = \frac{R}{4} = \frac{6}{4} = 1.5\,\Omega $
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