A wire of length $L$ $metre$ carrying a current of $I$ $ampere$ is bent in the form of a circle. Its magnitude of magnetic moment will be
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(b) If the radius of circle is $r$, then $2\pi r = L \Rightarrow r = \frac{L}{{2\pi }}$
Area $ = \pi {r^2} = \frac{{\pi {L^2}}}{{4{\pi ^2}}} = \frac{{{L^2}}}{{4\pi }}$
Magnetic moment $ = IA = \frac{{I{L^2}}}{{4\pi }}$
Area $ = \pi {r^2} = \frac{{\pi {L^2}}}{{4{\pi ^2}}} = \frac{{{L^2}}}{{4\pi }}$
Magnetic moment $ = IA = \frac{{I{L^2}}}{{4\pi }}$
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