Question
A wire stretches by a certain amount under a load. If the load and radius both are increased to four times, find the stretch caused in the wire.

Answer

$\text{Y}=\frac{\text{Fl}}{\text{A}\Delta\text{l}}\Rightarrow\Delta\text{l}=\frac{\text{Fl}}{\pi\text{r}^2\text{Y}}$ $\Delta\text{l}'=\frac{4\text{Fl}}{\pi(4\text{r})^2\text{Y}}=\frac{\text{Fl}}{4\pi\text{r}^2\text{Y}}=\frac{\Delta\text{l}}{4}.$

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