A wire suspended vertically from one end is stretched by attaching a weight $200 \,N$ to the lower end. The weight stretches the wire by $1 \,mm$. The elastic potential energy gained by the wire is ....... $J$
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(a)
Elastic potential energy $=\frac{1}{2} \times$ force $\times$ elongation
$=\frac{1}{2} \times 200 \times \frac{1}{1000}=0.1 \,J$
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