A wire $X$ of length $50\; cm$ carrying a current of $2\,A$ is placed parallel to a long wire $Y$ of length $5\,m$. The wire $Y$ carries a current of $3\,A$. The distance between two wires is $5\,cm$ and currents flow in the same direction. The force acting on the wire $Y$ is.
JEE MAIN 2022, Medium
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Force of interaction $=I_{1} \ell_{1} B_{12}$
$=\frac{\mu_{0} I _{1} I _{2}}{2 \pi r } \ell_{1}$
$=\frac{4 \pi \times 10^{-7} \times 6 \times 5}{2 \pi \times 5 \times 10^{-2}}$
$=1.2 \times 10^{-5} \text { towards } X$
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