MCQ
${A_2} + {B_2} \to 2AB;R.O.R = k{[{A_2}]^a}{[{B_2}]^b}$

Initial $[A_2]$ Initial $[B_2]$ $R.O.R.\,(r)\,Ms^{-1}$
$0.2$ $0.2$ $0.04$
$0.1$ $0.4$ $0.04$
$0.2$ $0.4$ $0.08$

Order of reaction with respect to $A_2$ and $B_2$ are respectively 

  • $a = 1, b = 1$
  • B
    $a = 2, b = 0$
  • C
     $a = 2, b = 1$
  • D
    None

Answer

Correct option: A.
$a = 1, b = 1$
a

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free