जीवा BC व ED एकमेकांना वर्तुळाच्या बाह्यभागात A बिंदूत छेदतात. $\therefore \angle C A E=\frac{1}{2}[m($ कंस $C E)- m ($ कंस BD $)]$ $=\frac{1}{2}\left(54^{\circ}-23^{\circ}\right)=\frac{1}{2} \times 31^{\circ}$ ∴ ∠CAE = 15.5°
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