MCQ
$ABC$ is a triangle with $B$ as right angle, $AC = 5\ cm$ and $AB = 4\ cm.$ A circle is drawn with $A$ as centre and $AC$ as radius. The length of the chord of this circle passing through $C$ and $B$ is:
- A$3\ cm$
- B$4\ cm$
- C$5\ cm$
- ✓$6\ cm$
✓
Answer
Correct option: D.
$6\ cm$
$AD$ and $AC$ are radii of same circle and $CD$ is a chord.
Consider $\triangle\text{ABC},$
$BC^2 = (AC)^2 - (AB)^2$
$=5^2 - 4^2 = 25 - 16 = 9$
$⇒ BC = 3\ cm$
Chord $CD = 2 × BC = 6\ cm$
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