MCQ
$ABCD$ is a rhombus. If $\angle\text{ACB} = 30^\circ,$ then $\angle\text{ADB}$ is:
- A$45^\circ$
- B$120^\circ$
- C$30^\circ$
- ✓$60^\circ$
If $\angle\text{ACB} = 30^\circ$ then $\angle\text{CAD} = 30^\circ$ (The diagonals bisect the angles in a Rhombus) and in $\triangle\text{AOD}, \ \angle\text{AOB} = 90^\circ$ diagonals perpendicular to each other, so by angle sum property of a $\angle\text{ADB} = 60^\circ.$
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