MCQ
Above conversion can be done by


- A$NaBH_4$
- ✓$LiAlH_4$
- C$PCC$
- D$KMnO_4$


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${C_{10}}{H_{22}} \xrightarrow{900\,K} {C_4}{H_8} + {C_6}{H_{14}}$
Product $(A)$ is

