MCQ
According to Bronsted-Lowry concept, the correct order of relative strength of bases follows the order
  • A
    $C{H_3}CO{O^ - } > C{l^ - } > O{H^ - }$
  • B
    $C{H_3}CO{O^ - } > O{H^ - } > C{l^ - }$
  • $O{H^ - } > C{H_3}CO{O^ - } > C{l^ - }$
  • D
    $O{H^ - } > C{l^ - } > C{H_3}CO{O^ - }$

Answer

Correct option: C.
$O{H^ - } > C{H_3}CO{O^ - } > C{l^ - }$
(c) Relative strength of bases can be shown by their conjugated acids.

Conjugate acid of $O{H^ - }$ is ${H_2}O$ which is a weak acid conjugate acid of $C{H_3}CO{O^ - }$ is $C{H_3}COOH$ which is stronger than ${H_2}O$. while conjugate acid of $C{l^ - }$ is $HCl$ which is strongest out of there. so the order of relative strength of bases is $O{H^ - } > C{H_3}CO{O^ - } > C{l^ - }$.

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