MCQ
According to $ IUPAC $ nomenclature sodium nitroprussied is named is
- ✓Sodium pentacyanidonitrosonium ferrat $(II)$
- BSodium nitroferricyanide
- CSodium nitroferrocyanide
- DSodium pentacyanonitrosyl ferrate $(II)$
✓
Answer
Correct option: A.
Sodium pentacyanidonitrosonium ferrat $(II)$
a
NO readily forms coordination complexes with transition metla ions. These complex are called nitrosyls. $F^{2+}$ and NO form the complex $\left[ Fe \left( H _{2} O \right)_{5} NO \right]^{2+}$ which is responsible for the colour in the brown ring test for nitrates. The colour is due to change transfer. This complex formally contains $F e(+1)$ and $N O^{+}$. Its magnetic moment is approximately $3.9 BM ,$ confirming the presence of three - unpaired electrons. Note that $N O^{+}$ is a strong field ligand, thus, it reshuffles the electronic configuration:
NO readily forms coordination complexes with transition metla ions. These complex are called nitrosyls. $F^{2+}$ and NO form the complex $\left[ Fe \left( H _{2} O \right)_{5} NO \right]^{2+}$ which is responsible for the colour in the brown ring test for nitrates. The colour is due to change transfer. This complex formally contains $F e(+1)$ and $N O^{+}$. Its magnetic moment is approximately $3.9 BM ,$ confirming the presence of three - unpaired electrons. Note that $N O^{+}$ is a strong field ligand, thus, it reshuffles the electronic configuration:
$F e^{+}\left(3 d^{6} 4 s^{1}\right) \rightarrow F e+\left(3 d^{7} 4 s^{0}\right)$
Most nitrosyl complexes are colourd. Another example is sodium nitroprusside $N a_{2}\left[F e(C N)_{5} N O\right] .2 H_{2} O$. The colour (brown - red) is again due to charge transfer. This complex has $N O^{+}$ as a ligands and $F e^{+}$ as the central metal ion. Thus, its IUPAC name should be sodium pentacyanidonitrosonium ferrat (II).
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