MCQ
According to law of photochemical equivalence the energy absorbed (in ergs/mole) is given as $(h = 6.62 \times 10^{-27} \ ergs,$$ \ c = 3 \times cm s^{-1}, $$\ N_A = 6.02 \times 10^{-23} \ mol^{-1})$
- ✓$\frac {1.196 \times 10^8}{\lambda}$
- B$\frac {2.859 \times 10^5}{\lambda}$
- C$\frac {2.859 \times 10^{16}}{\lambda}$
- D$\frac {1.196 \times 10^{16}}{\lambda}$
