MCQ
According to Le-Chatelier’s principal adding heat to a solid and liquid in equilibrium with endothermic nature will cause the
- ATemperature to rise
- BTemperature to fall
- ✓Amount of solid to decrease
- DAmount of liquid to decrease
✓
Answer
Correct option: C.
Amount of solid to decrease
(c)Solid + liquid $ \rightleftharpoons $ Solution $\Delta H$$=+ve$
Increase in temperature favours forward reaction.
Increase in temperature favours forward reaction.
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
The bond dissociation enthalpy of $H_2(g)$ and $N(g)$ are $436\ kJ\ mol^{-1}$ and $940\ kJ\ mol^{-1}$ and enthaply of formation of $NH_3$ is $- 45\ kJ\ moI^{-1}$ . The enthaply of atomisation of $NH_3$ is.....$kJ\ mol^{-1}$
→Which of the following has highest knocking property
In the given reaction
→${C_6}{H_5} - O - C{H_2} - C{H_3}\xrightarrow{{Excess\,HI/\Delta }}\left[ X \right] + \left[ Y \right]$
$[X]$ and $[Y]$ will respectively be
$N{a_2}{B_4}{O_7}\xrightarrow{x}{H_3}B{O_3}\xrightarrow{\Delta }{B_2}{O_3}\xrightarrow{y}B$
→Here $X, Y$ are respectively
If $‘X’$ is ionization energy of hydrogen then the energy required for excitation of $Li^{2+}$ electron from $2^{nd}$ excited state to $5^{th}$ excited state is
→One mole of calcium phosphide on reaction with excess water gives
What will be the formula of $'M'$ nitrate?
→If $0.01 \,M$ solution of an electrolyte has a resistance of $40 \,ohms$ in a cell having a cell constant of $0.4\,cm^{-1}$ then its molar conductance in $ohm^{-1}\, cm^2 \,mol^{-1}$ will be :-
→Which of the following is a buffer
The cell reaction $Mn + 2Ag_{\left( {{C_1}} \right)}^ + \left( {aq} \right) \to Mn_{\left( {{C_2}} \right)}^{ + 2}\left( {aq} \right) + 2Ag$ is represented by
→