MCQ
According to molecular orbital theory, the number of unpaired electron(s) in $\mathrm{O}_{2}^{2-}$ is :
- A$1$
- ✓$0$
- C$2$
- D$3$
$\sigma_{1 \mathrm{~s}}^{2} \sigma_{1 \mathrm{~s}}^{*} \sigma_{2 \mathrm{~s}}^{2} \sigma_{2 \mathrm{~s}}^{*_{2}}\left(\pi 2 \mathrm{p}_{\mathrm{x}}^{2}=\pi 2 \mathrm{p}_{\mathrm{y}}^{2}\right)\left(\pi_{2 \mathrm{px}}^{*}=\pi_{2 \mathrm{py}}^{*}\right)$
Zero unpaired electron
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Reason : $sp$ hybridised carbon atoms of acetylene are considerably electronegative.

$\mathrm{Sn}^{4+}, \mathrm{Sn}^{2+}, \mathrm{Pb}^{2+}, \mathrm{Tl}^{3+}, \mathrm{Pb}^{4+}, \mathrm{Tl}^{+}$