Bond order $= \frac{10-6}{2} = 2.0$
(Two unpaired electrons in antibonding molecular orbital)
$(2)$
Bond order $= \frac{10-5}{2} = 2.5$
(One unpaired electron in antibonding molecular orbital so it is paramagnetic)
${O_2} : {(\sigma 1s)^2}{({\sigma ^*}1s)^2}{(\sigma 2s)^2}{({\sigma ^*}2s)^2}{({\sigma ^*}2p_z)^2}$
$(\pi 2p_x^2 \equiv \pi 2p_y^2)\;({\pi ^*}2p_x^1 \equiv {\pi ^*}2p_y^1)\dots{(1)} $
${O_2^+} : {(\sigma 1s)^2}{({\sigma ^*}1s)^2}{(\sigma 2s)^2}{({\sigma ^*}2s)^2}{({\sigma ^*}2p_z)^2}$
$(\pi 2p_x^2 \equiv \pi 2p_y^2)\;({\pi ^*}2p_x^1 \equiv {\pi ^*}2p_y^0)\dots{(2)} $
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$(a)$ How many $g$ orbital are present in the $g$ subshell ?
$(b)$ In what principal electronic shell whould the $g$ subshell first occur and what is the total number of orbitals in this principal shell ?
${{O}_{(g)}}+{{e}^{-}}=O_{(g)}^{-}\Delta {{H}^{o}}=-142\ kJ\,mo{{l}^{-1}}$
$O_{(g)}^{-}+{{e}^{-}}=O_{(g)}^{2-}\Delta {{H}^{o}}=844\ kJ\,mo{{l}^{-1}}$
Identify product $B$ in above reaction sequence
${C_{(gr)}} + {O_{2(g)}} \to C{O_{2(g)}}\,\,\,\Delta H = x\,kJ/mol$
${C_{(gr)}} + \frac{1}{2}{O_{2(g)}} \to C{O_{(g)}}\,\,\,\Delta H = y\,kJ/mol$
$C{O_{(g)}} + \frac{1}{2}{O_{2(g)}} \to C{O_2}_{(g)}\,\,\,\Delta H = z\,kJ/mol$