MCQ
According to the Arrhenius equation,
  • A high activation energy usually implies a fast reaction
  • B
    Rate constant increases with increase in temperature. This is due to a greater number of collisions whose energy exceeds the activation energy
  • C
    Higher the magnitude of activation energy, stronger is the temperature dependence of the rate constant.
  • D
    The pre$-$exponential factor is a measure of the rate at which collisions occure, irrespective of their energy.

Answer

Correct option: A.
A high activation energy usually implies a fast reaction

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

The correct order of acidity for the following compounds is
The enol form of acetone, after treatment with ${D_2}O,$ gives
Which of the following does not show optical isomerism?
Match $List-I$ with $List-II$. 

$List-I$ $List-II$
$(A)$ $Cd ( s )+2 Ni ( OH )_{3}( s ) \rightarrow CdO ( s )+2 Ni ( OH )_{2}( s )+ H _{2} O (l)$ $(I)$ Primary battery
$(B)$  $Zn ( Hg )+ HgO ( s ) \rightarrow ZnO ( s )+ Hg (l)$ $(II)$ Discharging of secondary battery
$(C)$ $2 PbSO _{4}( s )+2 H _{2} O (l) \rightarrow Pb ( s )+ PbO _{2}( s )+ 2 H _{2} SO _{4}( aq )$ $(III)$ Fuel cell 
$(D)$ $2 H _{2}( g )+ O _{2}( g ) \quad \rightarrow 2 H _{2} O (l)$ $(IV)$ Charging of secondary battery

Choose the correct answer from the options given below.

A compound $A \to {C_5}{H_{10}}C{l_2}$ on hydrolysis gives ${C_5}{H_{10}}O$ which reacts with $N{H_2}OH$, forms iodoform but does not give fehling test. $A$ is
The compound $A$ in the following reaction is :

$A\xrightarrow[{(ii)\,\,Conc.\,{H_2}S{O_4}/\Delta }]{{{\text{(i)}}\,{\text{C}}{{\text{H}}_3}MgBr/{H_2}O}}$

$B\xrightarrow[{(ii)\,Zn/{H_2}O}]{{(i)\,{O_3}}}C + D$

$D\xrightarrow[\Delta ]{{Ba\left( {OH} \right)}}\begin{array}{*{20}{c}} {\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,C{H_3}} \\ {\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|} \\ {{H_3}C - C} \end{array}$$\begin{array}{*{20}{c}} {\,\,\,\,\,\,\,O} \\ {\,\,\,\,\,||} \\ { = CH - C - C{H_3}} \end{array}$

$CH_3 - CH = CH -CH_2 - CO_2H \xrightarrow[\Delta ]{}(X) \,(major)$; Product $(X)$ is
Reagents to carry out above conversion, $P, Q, R$ respectively are
A photo$-$cell employs photoelectric effect to convert:
Find out which of the following statement are true & False

$(a)$ Number of $S-S$ bonds in $H_2S_nO_6$ are $(n +1)$

$(b)$ When $F_2$ reacts with $H_2O$ it forms $HF,$ $O_2$ & $O_3.$

$(c)$ $XeF_6$ on hydrolysis shows disproportionation reaction

$(d)$ $Al$ metal on reacting with dilute $NaOH$ gives a white precipitate of $Al (OH)_3$ as a final product