MCQ
According to the molecular orbital theory, the bond order in ${C_2}$ molecule is
- A$0$
- B$1$
- ✓$2$
- D$3$
✓
Answer
Correct option: C.
$2$
(c) $B.O.$ of carbon $ = \frac{{{N_b} - {N_a}}}{2} = \frac{{8 - 4}}{2} = 2$.
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