MCQ
According to the molecular orbital theory, the bond order in ${C_2}$ molecule is
- A$0$
- B$1$
- ✓$2$
- D$3$
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$\begin{array}{*{20}{c}}
{C{H_3} - CH = CH - CH - CH - C{H_3}} \\
{{\mkern 1mu} {\mkern 1mu} {\mkern 1mu} \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,{\mkern 1mu} {\mkern 1mu} |{\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} \,\,\,\,\,\,\,\,\,\,\,{\mkern 1mu} {\mkern 1mu} |{\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} } \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,OH{\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} \,\,\,\,{\mkern 1mu} {\mkern 1mu} \,\,\,{\mkern 1mu} {\mkern 1mu} OH\,\,}
\end{array}\,$
$\begin{array}{*{20}{c}}
{C{H_3} - CH - CH = C{H_3}} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{C{H_3}\,\,\,\,\,\,\,\,\,\,\,\,}
\end{array}\xrightarrow{{HBr}}A$
$\begin{array}{*{20}{c}}
{C{H_3} - CH - CH = C{H_3}} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{C{H_3}\,\,\,\,\,\,\,\,\,\,\,\,}
\end{array}\xrightarrow{{HBr + ROOR}}B$
$\begin{array}{*{20}{c}}
{C{H_3} - CH - CH = C{H_3}} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{C{H_3}\,\,\,\,\,\,\,\,\,\,\,\,}
\end{array}\xrightarrow{{NBS}}C$
${B{orax}}\xrightarrow{X}{H_3}B{O_3}\xrightarrow{\Delta }{B_2}{O_3}\xrightarrow[\Delta ]{Y}B$,
$X$ and $Y$ are respectively
| list $I$ (species) | list $II$ ( $O-N-O$ angle) |
| $(A)$ $NO_2^+$ | $(1)$ $180^o$ |
| $(B)$ $NO_2$ | $(2)$ $132^o$ |
| $(C)$ $NO_2^-$ | $(3)$ $120^o$ |
| $(D)$ $NO_3^-$ | $(4)$ $115^o$ |
| $(5)$ $109^o$ |