MCQ
Acetic anhydride and ammonia gives the product :
- ✓$CH_3CONH_2$
- B$CH_3CONHCH_3$
- C$CH_3CN$
- D$CH_3COONH_4$
✓
Answer
Correct option: A.
$CH_3CONH_2$
a
Acetic anhydride reacts with ammonia to form acetamide $\left( CH _3 CONH _2\right)$.
Acetic anhydride reacts with ammonia to form acetamide $\left( CH _3 CONH _2\right)$.
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
The $RBC$ deficiency is deficiency disease of :
→Order of a reaction is decided by
Upon heating $KClO_3$ in the presence of catalytic amount of $MnO_2$, a gas $W$ is formed. Excess amount of $W$ reacts with white phosphorus to give $X$. The reaction of $X$ with $HNO_3$ gives $Y$ and $Z$.
→($1$) $W$ and $\mathbf{X}$ are, respectively
$[A]$ $O_3$ and $P_4 O_6$ $[B]$ $O_2$ and $P_4 O_6$ $[C]$ $O_2$ and $P_4 O_{10}$ $[D]$ $O_3$ and $P_4 O_{10}$
($2$) $Y$ and $Z$ are, respectively
$[A]$ $N_2 O_3$ and $\mathrm{H}_3 \mathrm{PO}_4$
$[B]$ $N_2 O_5$ and $\mathrm{HPO}_3$
$[C]$ $N_2 O_4$ and $HPO_3$
$[D]$ $N_2 O_4$ and $H_3 PO_3$
Give the answer of quetion ($1$) and ($2$)
The osmotic pressure of a dilute solution is directly proportional to the
Which compound is not a monobasic acid ?
The rate of a reaction $A$ doubles on increasing the temperature from $300$ to $310\, K$. By how much, the temperature of reaction $B$ should be increased from $300\, K$ so that rate doubles if activation energy of the reaction $B$ is twice to that of reaction $A$. ......... $K$
→To protect iron against corrosion, the most durable metal plating on it, is
$x,\, y$ and $z$ are respectively
→$MnO_4^ - \, + \,x{e^ - }\,\xrightarrow[{(Alkaline\,\,medium)}]{}MnO_4^{2 - }$
$MnO_4^ - \, + \,y{e^ - }\,\xrightarrow{{(Acidic\,\,medium)}}M{n^{2 + }}$
$MnO_4^ - \, + \,z{e^ - }\,\xrightarrow{{(Neutral\,\,medium)}}Mn{O_2}$
The instantaneous rate of disappearance of $MnO_4^-$ ion in the following reaction is $4.56\times10^{-3}\,Ms^{-1}$, $2MnO_4^-+ 10I^-+ 16 H^+ \to 2 Mn^{2+} + 5I_2 + 8H_2O$ The rate of appearance $I_2$ is
→The major product of the following reaction is
→$[Figure]$ $\xrightarrow[{S_N2}]{{KOH}}$