MCQ
Acetoacetic ester behaves as
- AAn unsaturated hydroxy compound
- BA keto compound
- ✓Both of these ways
- DNone of these
✓
Answer
Correct option: C.
Both of these ways
c
(c)$\underset{\begin{smallmatrix}
\text{Acetoacetic ester} \\
\text{ ( keto form)}
\end{smallmatrix}}{\mathop{C{{H}_{3}}-\overset{O}{\mathop{\overset{||}{\mathop{C}}\,}}\,-C{{H}_{2}}-\overset{O}{\mathop{\overset{||}{\mathop{C}}\,}}\,-O-{{C}_{2}}{{H}_{5}}}}\,$ $ \rightleftharpoons $
$\mathop {C{H_3} - \mathop {\mathop C\limits^| = }\limits^{OH} CH - \mathop {\mathop C\limits^{||} }\limits^O - O - {C_2}{H_5}}\limits_{{\rm{(enolic form)}}} $
(c)$\underset{\begin{smallmatrix}
\text{Acetoacetic ester} \\
\text{ ( keto form)}
\end{smallmatrix}}{\mathop{C{{H}_{3}}-\overset{O}{\mathop{\overset{||}{\mathop{C}}\,}}\,-C{{H}_{2}}-\overset{O}{\mathop{\overset{||}{\mathop{C}}\,}}\,-O-{{C}_{2}}{{H}_{5}}}}\,$ $ \rightleftharpoons $
$\mathop {C{H_3} - \mathop {\mathop C\limits^| = }\limits^{OH} CH - \mathop {\mathop C\limits^{||} }\limits^O - O - {C_2}{H_5}}\limits_{{\rm{(enolic form)}}} $
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