MCQ
Acetonitrile is:
- A${C_2}{H_5}CN$
- ✓$C{H_3}CN$
- C$C{H_3}COCN$
- D${C_6}{H_5}C{H_2}CN$
✓
Answer
Correct option: B.
$C{H_3}CN$
b
(b)$C{H_3}CN$is called acetonitrile....
(b)$C{H_3}CN$is called acetonitrile....
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Consider the following reaction, the rate expression of which is given below
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$\text { rate }=\mathrm{k}[\mathrm{A}]^{1 / 2}[\mathrm{~B}]^{1 / 2}$
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{(2){\kern 1pt} A{g_2}O/{H_2}O} \\
{(3){\kern 1pt} \Delta }
\end{array}}]{{(1){\kern 1pt} \,excess\,{\kern 1pt} C{H_3}I/{K_2}C{O_3}}}(B)$ $\xrightarrow[{(iii){\kern 1pt} \Delta }]{{\begin{array}{*{20}{c}}
{(i){\kern 1pt} excess{\kern 1pt} C{H_3}I/{K_2}C{O_3}} \\
{(ii){\kern 1pt} A{g_2}O}
\end{array}}}$ $\begin{array}{*{20}{c}}
{{H_2}C = CH - CH - CH = C{H_2}} \\
{|{\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} } \,\,\,\,\\
{{\mkern 1mu} {\mkern 1mu} C{H_3}}
\end{array}$
→{(2){\kern 1pt} A{g_2}O/{H_2}O} \\
{(3){\kern 1pt} \Delta }
\end{array}}]{{(1){\kern 1pt} \,excess\,{\kern 1pt} C{H_3}I/{K_2}C{O_3}}}(B)$ $\xrightarrow[{(iii){\kern 1pt} \Delta }]{{\begin{array}{*{20}{c}}
{(i){\kern 1pt} excess{\kern 1pt} C{H_3}I/{K_2}C{O_3}} \\
{(ii){\kern 1pt} A{g_2}O}
\end{array}}}$ $\begin{array}{*{20}{c}}
{{H_2}C = CH - CH - CH = C{H_2}} \\
{|{\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} } \,\,\,\,\\
{{\mkern 1mu} {\mkern 1mu} C{H_3}}
\end{array}$
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