MCQ
Acidified $K_2Cr_2O_7$ solution turns green when $Na_2SO_3$ is added to it. This is due to the formation of
- ✓$Cr_2(SO_4)_3$
- B$CrO_4^{2-}$
- C$Cr_2(SO_3)_3$
- D$CrSO_4$
✓
Answer
Correct option: A.
$Cr_2(SO_4)_3$
a
$K_{2} C r_{2} O_{7}$ is oxidising reagent.
$K_{2} C r_{2} O_{7}$ is oxidising reagent.
$K_{2} C r_{2} O_{7}+3 N a_{2} S O_{3}+4 H_{2} S O_{4} \rightarrow$ $3 N a_{2} S O_{4}+K_{2} S O_{4}+C r_{2}\left(S O_{4}\right)_{3}+4 H_{2} O$
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