- ✓$H_2S < H_2Se < H_2Te$
- B$H_2Se < H_2S < H_2Te$
- C$H_2Te < H_2S < H_2Se$
- D$H_2Se < H_2Te < H_2S$
It contains sulfur in its +6 oxidation state and a peroxide group.
The tetrathionate anion, $\mathrm{S}_{4} \mathrm{O}_{6}^{2-}$, is a sulphur oxoanion derived from the compound tetrathionic acid, $\mathrm{H}_{2} \mathrm{S}_{4} \mathrm{O}_{6}$.
Two of the sulphur atoms present in the ion are in oxidation state $\mathrm{O}$ and two are in oxidation state $+5 .$
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$(i)$ A $0.5\,m$ $NaBr$ solution has a higher vapour pressure than a $0.5\,m\,BaCl_2$ solution at the same temperature
$(ii)$ Pure water freezes at the higher temperature than pure methanol
$(iii)$ a $0.1\,m\,NaOH$ solution freezes at a lower temperature than pure water
Choose the correct answer from the codes given below
$(I)\,\, O_3 \to $ product
$(II)\,\,C{r_2}O_7^{ - 2}\xrightarrow{{{H^ + }}}$ product
$(III)\,\,MnO_4^\Theta \xrightarrow{{{H^ + }}}$ product
$(IV)\,\, H_2S \to $ product
