Question
Add $1\frac14$ and $6\frac12.$
✓
Answer
We have, $1\frac{1}4{}+6\frac12$$=\frac{1\times4+1}{4}+\frac{6\times2+1}{2}$
$\because$ Mixed fraction = Improper fraction $=\frac{\text{Whole number×Denominator+Numerator}}{\text{Denominator}}$
$=\frac{5}{4}+\frac{13}{2}=\frac{5\times1}{4\times1}+\frac{13\times2}{2\times2}$[$\because$ $LCM$ of $4$ and $2$ is $4$, so convet each fraction to an equivalent fraction with denominator $12$]
$=\frac{5}{4}+\frac{26}{4}$
$=\frac{5+26}{4}=\frac{31}{4}=7\frac34$
$\because$ Mixed fraction = Improper fraction $=\frac{\text{Whole number×Denominator+Numerator}}{\text{Denominator}}$
$=\frac{5}{4}+\frac{13}{2}=\frac{5\times1}{4\times1}+\frac{13\times2}{2\times2}$[$\because$ $LCM$ of $4$ and $2$ is $4$, so convet each fraction to an equivalent fraction with denominator $12$]
$=\frac{5}{4}+\frac{26}{4}$
$=\frac{5+26}{4}=\frac{31}{4}=7\frac34$
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