Question
Add: $2 p^4-3 p^3+p^2-5 p+7,-3 p^4-7 p^3-3 p^2-p-12$

Answer

$ \left(2 p^4-3 p^3+p^2-5 p+7\right)+\left(-3 p^4-7 p^3-3 p^2-p-12\right) $
$ =2 p^4-3 p^3+p^2-5 p+7-3 p^4-7 p^3-3 p 2-p-12 $
$ =\left(2 p^4-3 p^4\right)+\left(-3 p^3-7 p^3\right)+\left(p^2-3 p^2\right)+(-5 p-p)+(7-12) $
$ =-p^4-10 p^3-2 p^2-6 p-5 $

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