Question
Add the following rational numbers:
$\frac{1}{9}\text{ and }\frac{4}{-27}$
$\frac{1}{9}\text{ and }\frac{4}{-27}$
✓
Answer
$\frac{1}{9}\text{ and }\frac{4}{-27}$
$\frac{-1}{9}=\frac{1\times(-1)}{-9\times(-1)}=\frac{-1}{9}$
$=\frac{-1\times3}{9\times3}=\frac{-3}{27}$
$\frac{4}{-27}=\frac{4\times(-1)}{-27\times(-1)}=\frac{-4}{27}$
$=\frac{-3+(-4)}{27}=\frac{-3-4}{27}$
$=\frac{-7}{27}$
$\frac{-1}{9}=\frac{1\times(-1)}{-9\times(-1)}=\frac{-1}{9}$
$=\frac{-1\times3}{9\times3}=\frac{-3}{27}$
$\frac{4}{-27}=\frac{4\times(-1)}{-27\times(-1)}=\frac{-4}{27}$
$=\frac{-3+(-4)}{27}=\frac{-3-4}{27}$
$=\frac{-7}{27}$
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