Question
Add the following rational numbers: $-3\text{ and }\frac{3}{5}$
✓
Answer
$\frac{-3}{1}\text{ and }\frac{3}{5}$
If $\frac{\text{p}}{\text{q}}$ and $\frac{\text{r}}{\text{s}}$ are two rational numbers such that $q$ and $s$ do not have a common factor.
$\frac{\text{p}}{\text{q}}+\frac{\text{r}}{\text{s}}=\frac{\text{p}\times\text{s}+\text{r}\times\text{q}}{\text{q}\times\text{s}}$
$\frac{3}{1}+\frac{3}{5}=\frac{5\times(-3)+(3)\times1}{5}$
$=\frac{-15+3}{5}$
$=\frac{-12}{5}$
If $\frac{\text{p}}{\text{q}}$ and $\frac{\text{r}}{\text{s}}$ are two rational numbers such that $q$ and $s$ do not have a common factor.
$\frac{\text{p}}{\text{q}}+\frac{\text{r}}{\text{s}}=\frac{\text{p}\times\text{s}+\text{r}\times\text{q}}{\text{q}\times\text{s}}$
$\frac{3}{1}+\frac{3}{5}=\frac{5\times(-3)+(3)\times1}{5}$
$=\frac{-15+3}{5}$
$=\frac{-12}{5}$
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
Evaluate:
$\Big(\frac{6\times10}{2^{2}\times5^{3}}\Big)^{2}\times\frac{25}{27}$
→$\Big(\frac{6\times10}{2^{2}\times5^{3}}\Big)^{2}\times\frac{25}{27}$
A rectangular field is $50m$ by $40m$. It has two roads through its centre, running parallel to its sides. The width of the longer and the shorter roads are $2m$ and $2.5-m$-respectively. Find the area of the roads and the area of the remaining portion of the field.
→In the adjoining figure, $P$ and $Q$ are two points on equal sides $AB$ and $AC$ of an isosceles triangle $ABC$ such that $AP = AQ.$ Prove that $BQ = CP.$
→The bisectors of the acute angles of a right triangle meet at $O$. Find the angle at $O$ between the two bisectors.
→Find five rational numbers between $-3$ and $-2.$
→In the given figure, $ABCD$ is a rectangle with length $= 36m$ and breadth $= 24m$. In $\triangle\text{ADE},\text{EF}\perp\text{AD}$ and $EF = 15\ m$. Calculate the area of the shaded region.
→Find the difference of:
$3 \frac{3}{10}$ and $2 \frac{7}{15}$
→$3 \frac{3}{10}$ and $2 \frac{7}{15}$
Solve the following equation. Also, verify the result.
$m-\frac{m-1}{2}=1-\frac{m-2}{3}$
→$m-\frac{m-1}{2}=1-\frac{m-2}{3}$
A person deposits ₹ 25000 in a firm who pays an interest at the rate of $20 \%$ per annum. Calculate the income he gets from it annually.
→Find the area of a rectangular park which is $41\frac{2}{3}\text{m}$ long and $18$$18\frac{3}{5}\text{m}$ broad.
→