Question
Add the following rational numbers:
$\frac{9}{-13}\text{ and }\frac{-11}{-13}$
$\frac{9}{-13}\text{ and }\frac{-11}{-13}$
✓
Answer
$\frac{9}{-13}\text{ and }\frac{-11}{-13}$
$\frac{9}{-13}=\frac{9\times(-1)}{-13\times(-1)}=\frac{-9}{13}$
$\frac{-11}{-13}=\frac{-11\times(-1)}{-13\times(-1)}=\frac{11}{13}$
$\therefore\frac{-9}{13}+\frac{11}{13}=\frac{-9+11}{13}$
$=\frac{2}{13}$
$\frac{9}{-13}=\frac{9\times(-1)}{-13\times(-1)}=\frac{-9}{13}$
$\frac{-11}{-13}=\frac{-11\times(-1)}{-13\times(-1)}=\frac{11}{13}$
$\therefore\frac{-9}{13}+\frac{11}{13}=\frac{-9+11}{13}$
$=\frac{2}{13}$
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