Question
Add:
$x^2-a^2,-5 x^2+2 a^2,-4 x^2+4 a^2$
$x^2-a^2,-5 x^2+2 a^2,-4 x^2+4 a^2$
✓
Answer
$x^2-a^2,-5 x^2+2 a^2,-4 x^2+4 a^2$
$=x^2-a^2+\left(-5 x^2\right)+2 a^2+\left(-4 x^2\right)+4 a^2$
$=x^2-a^2-5 x^2+2 a^2-4 x^2+4 a^2$
$=\left(x^2-5 x^2-4 x^2\right)-\left(a^2-2 a^2-4 a^2\right)$
$=x^2-9 x^2-\left(a^2-6 a^2\right)$
$=8 x^2-\left(-5 a^2\right)$
$=-8 x^2+5 a^2=5 a^2-8 x^2$
$=x^2-a^2+\left(-5 x^2\right)+2 a^2+\left(-4 x^2\right)+4 a^2$
$=x^2-a^2-5 x^2+2 a^2-4 x^2+4 a^2$
$=\left(x^2-5 x^2-4 x^2\right)-\left(a^2-2 a^2-4 a^2\right)$
$=x^2-9 x^2-\left(a^2-6 a^2\right)$
$=8 x^2-\left(-5 a^2\right)$
$=-8 x^2+5 a^2=5 a^2-8 x^2$
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