Download App

Complex Numbers — Maths STD 11 Science — Question

Maharashtra BoardEnglish MediumSTD 11 ScienceMathsComplex Numbers2 Marks
MCQ
Additive inverse of $1- i$ is
  • A
    $0+0 i$
  • B
    $-1- i$
  • ✓
    $-1+i$
  • D
    $1-i$
✓

Answer

Correct option: C.
$-1+i$
(C)
If $z =x+ i y$ is the additive inverse of $1- i$,
then $(x+ i y)+(1- i )=0$
$\Rightarrow x+1=0, y-1=0 \Rightarrow x=-1, y=1$
∴ The additive inverse of $1- i$ is $z =-1+ i$.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "MCQ" from Complex Numbers→Complex Numbers — all question types→Maths STD 11 Science question papers→Maharashtra Board STD 11 Science question papers→Maharashtra Board question paper generator→

Similar questions

Let $t_n$ denote the $n^{\text {th }}$ term of the infinite serion $\frac{1}{1!}+\frac{10}{2!}+\frac{21}{3!}+\frac{34}{4!}+\frac{49}{5!}+\ldots$ . Then $\lim _{n \rightarrow \infty} t _{ n }$ is
→
$1+\cos ^2 2 A$ is equal to
→
If the functions $f, g, h$ are defined from the sets of real numbers $R$ to $R$ such that
$f(x)=x^2-1, g(x)=\sqrt{x^2+1}, h(x)=\left\{\begin{array}{l}0, \text { if }{ }_{x=0} \\x, \text { if }{ }_{x>0} ,\end{array}\right.$
then the composite function $(hofog)(x)=$
→
Equations of diagonals of square formed by lines x = 0, y = 0, x = 1 and y = 1 are
→
The equation of the ellipse whose foci are ( $\pm 5,0$ ) and one of its directrix is 5x = 36 is
→
If the lines ax y + 1 = 0, x + by + 1 = 0 and x + y + c = 0 (a, b, c being distinct and different from 1) are concurrent, then $\frac{1}{1-a}+\frac{1}{1-b}+\frac{1}{1-c}=$
→
If $R$ is a relation from a finite set $A$ having m elements of a finite set $B$ having $n$ elements, then the number of relations from $A$ to $B$ is:
→
Range of the function $f (x)=\sqrt{x^2+x+1}$ is equal to
→
A man speaks truth 2 out of 3 times. He picks one of the natural numbers in the set $S=\{1,2,3,4,5,6,7\}$ and reports that it is even. The probability that it is actually even is
→
If $(1+\text{i})(1+2\text{i})(1+3\text{i})...(1+\text{ni})=\text{a}+\text{ib},$ then $2.5.10.17 ... (1+\text{n}^2)=$
→