MCQ
Additive inverse of $1 - i$is
- A$0 + 0i$
- B$ - 1 - i$
- ✓$ - 1 + i$
- DNone of these
==> $x + 1 = 0$, $y - 1 = 0$
==> $x = - 1$, $y = 1$
$\therefore $ The additive inverse of $1 - i$is $z = - 1 + i$
Trick : Since $(1 - i) + ( - 1 + i) = 0$.
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where $[x]$ is the greatest integer less than or equal to $x$, then the value of $\alpha$ is :
$STATEMENT -1$ : For each real $\mathrm{t}$, there exists a point $\mathrm{c}$ in $[\mathrm{t}, \mathrm{t}+\pi]$ such that $\mathrm{f}^{\prime}(\mathrm{c})=0$. because
$STATEMENT -2$: $f(t)=f(t+2 \pi)$ for each real $t$.