MCQ
After completion of $'np\ ’$ level, the electron enters into which level according to $\ce{(n + p)}$ rule?
  • A
    $\ce{(n − 1)d}$
  • $\ce{(n + 1)s}$
  • C
    $\ce{nd}$
  • D
    $\ce{(n + 1)p}$

Answer

Correct option: B.
$\ce{(n + 1)s}$
Energy of nd level would be higher than $\ce{(n + 1)s}.$
$\ce{nd = n + 2, (n + 1)s = n + 1}.$
So, electron will enter into lower energy level.
i.e, $\ce{(n + 1)s}$
Let us take an example of $'4p\ '$ orbital.
As per Moeller diagram, the orbital that will be filled after $'4p\ '$ orbital is $'5s\ '.$

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