MCQ
After filling the $4d-$ orbitals, an electron will enter in :
- A$4p$
- B$4s$
- ✓$5p$
- D$4f$
The $4 d$ sub-energy level is at a lower energy than the $5 p$ sub-energy level
For $4 d , n =4$ and $1=2$. Hence, $( n +l)=4+2=6$
For $5 p , n =5$ and $1=1$. Hence, $( n +l)=5+1=6$
As the value of $(n+l)$ for $4 d$ orbital is same as that of $5 p$ orbital, $4 d$ orbital is filled before $5 p$ orbital as $4 d$ orbital has lower value of $n$ than $5 p$ orbital.
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