MCQ
Aldehydes and ketones can be reduced to hydrocarbon by using
- A$LiAl{H_4}$
- B${H_2}/Pd - BaS{O_4}$
- C$Na - Hg/HCl$
- ✓$N{H_2} - N{H_2}/{C_2}{H_5}ONa$
$N{H_2} - N{H_2}/O{H^ - }/{C_2}{H_5}ONa$
used to the reduction of $ - \mathop C\limits^{_{||}^O} - $group into $ - C{H_2} - $ group.
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Reason : There is delocalisation of electrons from filled $d$ orbitals into the empty orbitals on the $CO$ ligands.