Question
$A=\left[\begin{array}{cc}1 & 2 \\ -2 & 3\end{array}\right]$ and $B=\left[\begin{array}{cc}-2 & -1 \\ 1 & 2\end{array}\right], C\left[\begin{array}{cc}0 & 3 \\ 2 & -1\end{array}\right]$ Find $A+2 B-3 C$

Answer

$\begin{aligned} & A=\left[\begin{array}{cc}1 & 2 \\ -2 & 3\end{array}\right] \text { and } B=\left[\begin{array}{cc}-2 & -1 \\ 1 & 2\end{array}\right], C\left[\begin{array}{cc}0 & 3 \\ 2 & -1\end{array}\right] \\ & \therefore A+2 B-3 C \\ & =\left[\begin{array}{cc}1 & 2 \\ -2 & 3\end{array}\right]+2\left[\begin{array}{cc}-2 & -1 \\ 1 & 2\end{array}\right]-3\left[\begin{array}{cc}0 & 3 \\ 2 & -1\end{array}\right] \\ & =\left[\begin{array}{cc}1 & 2 \\ -2 & 3\end{array}\right]+\left[\begin{array}{cc}-4 & -2 \\ 2 & 4\end{array}\right]-\left[\begin{array}{cc}0 & 9 \\ 6 & -3\end{array}\right] \\ & =\left[\begin{array}{cc}1-4-0 & 2-2-9 \\ -2+2-6 & 3+4+3\end{array}\right] \\ & =\left[\begin{array}{cc}-3 & -9 \\ -6 & 10\end{array}\right] .\end{aligned}$

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