- A$\mathrm{C}_2 \mathrm{H}_6$
- B$\mathrm{C}_4 \mathrm{H}_{10}$
- C$\mathrm{C}_5 \mathrm{H}_{12}$
- ✓$\mathrm{C}_6 \mathrm{H}_{14}$
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$3.0$ $moles$ of $\mathrm{PCl}_{5}$ is introduced in a $1\, \mathrm{~L}$ closed reaction vessel at $380\, \mathrm{~K}$. The number of moles of $\mathrm{PCl}_{5}$ at equilibrium is $.....\,\times 10^{-3}$. (Round off to the Nearest Integer)
$(i)$ $\begin{array}{*{20}{c}}
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,C{H_3}} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|} \\
{C{H_3} - {C^ \mathbf{-} }} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,C{H_3}}
\end{array}$
$(ii)$ $H _{2} C = CH - CH _{2}$
$(iii)$ $HC \equiv \stackrel{\ominus}{ C }$
$(iv)$ $\stackrel{\ominus}{ CH _{3}}$
$(v)$ $\stackrel{\ominus}{{ }_{ CN }}$