- AHydrolysis by dil. ${H_2}S{O_4}$
- BHydration of alkene by alkaline $KMn{O_4}$
- CHydrolysis by water vapours and conc. ${H_2}S{O_4}$
- ✓Both $(b)$ and $(c)$
$\underset{\text{Ethene}}{\mathop{C{{H}_{2}}=C{{H}_{2}}}}\,+{{H}_{2}}O\xrightarrow{\text{Conc}\text{.}{{H}_{2}}S{{O}_{4}}}\underset{\text{Ethanol}}{\mathop{C{{H}_{3}}-C{{H}_{2}}-OH}}\,$
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$\left.\left. K _3\left[ Fe ( CN )_6\right]( K ),\left[ Co \left( NH _3\right)_6\right] Cl _3( L ), Na _3[ Co \text { (oxalate })_3\right]( M ),\left[ Ni _2 H _2 O \right)_6\right] Cl _2( N ) \text {, }$ $K _2\left[ Pt ( CN )_4\right]( O ) \text { and }\left[ Zn \left( H _2 O \right)_6\right]\left( NO _3\right)_2( P ) $ the diamagnetic complexes are

$1.$ Among the following, the correct statement is
$(A)$ Phosphates have no biological significance in humans
$(B)$ Between nitrates and phosphates, phosphates are less abundant in earth's crust
$(C)$ Between nitrates and phosphates, nitrates are less abundant in earth's crust
$(D)$ Oxidation of nitrates is possible in soil
$2.$ Among the following, the correct statement is
$(A)$ Between $\mathrm{NH}_3$ and $\mathrm{PH}_3, \mathrm{NH}_3$ is better electron donor because the lone pair of electrons occupies spherical ' $\mathrm{s}$ ' orbital and is less directional
$(B)$ Between $\mathrm{NH}_5$ and $\mathrm{PH}_5, \mathrm{PH}_5$ is better electron donor because the lone pair of electrons occupies $\mathrm{sp}^3$ orbital and is more directional
$(C)$ Between $\mathrm{NH}_3$ and $\mathrm{PH}_3, \mathrm{NH}_3$ is a better electron donor because the lone pair of electrons occupies $\mathrm{sp}^3$ orbital and is more directional
$(D)$ Between $\mathrm{NH}_3$ and $\mathrm{PH}_3, \mathrm{PH}_3$ is better electron donor because the lone pair of electrons occupies spherical ' $\mathrm{s}$ ' orbital and is less directional
$3.$ White phosphorus on reaction with $\mathrm{NaOH}$ gives $\mathrm{PH}_3$ as one of the products. This is a
$(A)$ dimerization reaction
$(B)$ disproportionation reaction
$(C)$ condensation reaction
$(D)$ precipitation reaction
Give the answer question $1,2$ and $3.$
$(I)$ Ortho -nitrophenol
$(II)$ Para -nitrophenol
$(III)$ Meta- nitrophenol