Alkylamine dissolve in hydrochloric acid to form alkylammonium chloride. The nitrogen in the latter salt is:
A
Quadricovalent only
B
Tricovalent only
C
Unielectrovalent only
D
Quadricovalent, Unielectrovalent
Difficult
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D
Quadricovalent, Unielectrovalent
d Alkylamine dissolve in hydrochloric acid to form alkylammonium chloride. The nitrogen in the latter salt is quadricovalent, unielectrovalent.
Quadricovalent means that nitrogen can form $4$ covalent bonds. Unielectrovalent means that nitrogen forms a singly charged ion.
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Number of compounds from the following which cannot undergo Friedel-Crafts reactions is ............ toluene, nitrobenzene, xylene, cumene, anline, chlorobenzene, $m$-nitroaniline, $m$-dinitrobenzene