Question
All prime numbers are odd.

Answer

 
$2$ $63,70,77$
$3$ $63,35,77$
$3$ $21,35,77$
$5$ $7,35,77$
$7$ $7,7,77$
$11$ $1,1,11$
  $1,1,$

$\therefore L.C.M$. of $63, 70$ and $77 = 2 \times 3 \times 3 \times 5 \times 7 \times 11$
$= 6930$
Hence, the minimum distance each should cover so that all cover the distance in complete steps is $6930\ cm.$

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