MCQ
All $Zn( +II)$ compounds are white because
- ✓$Zn^{2+}$ has a $d^{10}$ configuration and the $d-$ subshell is full
- B$Zn^{2+}$ shows $d-d$ transition
- C$Zn^{2+}$ has no electron in the $4s-$ subshell
- D$Zn$ is not a transition element
✓
Answer
Correct option: A.
$Zn^{2+}$ has a $d^{10}$ configuration and the $d-$ subshell is full
a
The electronic configuration of $Zn ^{2+}$ is $3 d ^{10} 4 s ^0$. All the electrons are paired. Hence, all $Zn ^{2+}$ compounds are colorless or white.
The electronic configuration of $Zn ^{2+}$ is $3 d ^{10} 4 s ^0$. All the electrons are paired. Hence, all $Zn ^{2+}$ compounds are colorless or white.
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