MCQ
Aluminium $(III)$ chloride forms a dimer because
- ✓Higher coordination number can be achieved by aluminium
- BAluminium has high ionization energy
- CAluminium belongs to $III$ group
- DIt cannot form a trimer
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$(A)$ $E, F$ and $\mathrm{G}$ are resonance structures
$(B)$ $E, F$ and $E, G$ are tautomers
$(C)$ $\mathrm{F}$ and $\mathrm{G}$ are geometrical isomers
$(D)$ $\mathrm{F}$ and $\mathrm{G}$ are diasteromers

Possible number of elimination products (alkene) of the given reaction is?