MCQ
$a^m \times a^n$ is equal to:
- A$\left(a^2\right)^{m n}$
- B$a^{m-n}$
- ✓$a^{m+n}$
- D$a^{m n}$
✓
Answer
Correct option: C.
$a^{m+n}$
We know that, if $‘a’$ is a rational number, $m$ and $n$ are natural numbers, then.
$a^m \times a^n=a^{m+n}$
$a^m \times a^n=a^{m+n}$
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