MCQ
Ambidentate ligand is :
- A$Cl ^{-}$
- B$H _2 O$
- C$NH _3$
- ✓$NO _2^{-}$
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| (a) Pure nitrogen | (i) Chlorine |
| (b) Haber process | (ii) Sulphuric acid |
| (c) Contact process | (iii) Ammonia |
| (d) Deacon's process | (iv) Sodium azide or Barium azide |
Which of the following is the correct option ?
$(a)\quad (b)\quad (c) \quad (d)$
The final product formed in the above reaction sequence is
$\underset{I}{\mathop{C{{H}_{3}}-C{{H}_{2}}-N{{H}_{2}}}}\,$
$\underset{II}{\mathop{{{(C{{H}_{3}}C{{H}_{2}})}_{2}}NH}}\,$
$\mathop {{{(C{H_3}C{H_2})}_3}N}\limits_{II} $
$E_{{A^{3 + }}/A}^o = 1.50\,\,V\,,$ $E_{{B^{2 + }}/B}^o = 0.3\,\,V,$
$E_{{C^{3 + }}/C}^o = - \,0.74\,\,V,$ $E_{{D^{2 + }}/D}^o = - \,2.37\,\,V.$
The correct sequence in which the various metals are deposited at the cathode is