Ametallic conductor of irregular cross-section is as shown in the figure. Aconstant potential difference is applied across the ends $(1)$ and $(2)$. Then :
Athe current at the cross-section $P$ equals the current at the cross-section $Q$
Bthe electric field intensity at $P$ is less than that at $Q.$
Cthe rate of heat generated per unit time at $Q$ is greater than that at $P$
D
All of the above
Diffcult
Download our app for free and get started
D
All of the above
d $(A) I_{P}=I_{Q}$
$(B) J=\sigma E$
$J_{P} < J_{Q}$
$E p < E_{Q}$
$(C)$ $H=I^{2} R \& R \propto \frac{1}{A}$
$R_{P} < R_{Q}$
$H_{P} < H_{Q}$
Download our app
and get started for free
Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*
By which of the following single load resistance the load bridge should be replaced so that the power to the load remains unchanged ................ $\Omega$
In the given circuit diagram, the currents, ${I_1} = - \,0.3\,A,\,{I_4} = 0.8\,A$ and ${I_5} = 0.4\,A,$ are flowing as shown. The currents $I_2,\,I_3$ and $I_6,$ respectively are
A potentiometer wire $AB$ having length $L$ and resistance $12\, r$ is joined to a cell $D$ of $emf$ $\varepsilon $ and internal resistance $r$. A cell $C$ having $emf$ $\varepsilon /2$ and internal resistance $3r$ is connected. The length $AJ$ at which the galvanometer as shown in figure shows no deflection is