Question
Amisha has a square plot of side $m$ and another triangular plot with base and height each equal to $m.$ What is the total area of both plots$?$
✓
Answer
Given,
Side of square plot $=\mathrm{m}$ and height and base of triangular plot $=\mathrm{m}$
$\because$ Area of square plot $=\mathrm{m}^2$
$\left[\because\right.$ Area of square $\left.=(\text { side })^2\right]$
$\therefore$ Area of triangular plot $=\frac{1}{2} \times \mathrm{m} \times \mathrm{m}=\frac{\mathrm{m}^2}{2}$
$\left[\because\right.$ area of triangle $=\frac{1}{2} \times$ height $\times$ base $]$
$\therefore$ Totel of both $=$ area of square plot + area of tringular plot
$\mathrm{m}^2+\frac{\mathrm{m}^2}{2}=\frac{2 \mathrm{~m}^2+\mathrm{m}^2}{2}=\frac{3 \mathrm{~m}^2}{2}$
$[$Taking $LCM$ of $1$ and $2$ is $2 ]$
Side of square plot $=\mathrm{m}$ and height and base of triangular plot $=\mathrm{m}$
$\because$ Area of square plot $=\mathrm{m}^2$
$\left[\because\right.$ Area of square $\left.=(\text { side })^2\right]$
$\therefore$ Area of triangular plot $=\frac{1}{2} \times \mathrm{m} \times \mathrm{m}=\frac{\mathrm{m}^2}{2}$
$\left[\because\right.$ area of triangle $=\frac{1}{2} \times$ height $\times$ base $]$
$\therefore$ Totel of both $=$ area of square plot + area of tringular plot
$\mathrm{m}^2+\frac{\mathrm{m}^2}{2}=\frac{2 \mathrm{~m}^2+\mathrm{m}^2}{2}=\frac{3 \mathrm{~m}^2}{2}$
$[$Taking $LCM$ of $1$ and $2$ is $2 ]$
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