MCQ
Among $H_2O, H_2S, H_2Se$ and $H_2Te$. The one with the highest boiling point is
- A$H_2O$ because of hydrogen bonding
- B$H_2Te$ because of higher molecular weight
- C$H_2S$ because of hydrogen bonding
- ✓$H_2Se$ because of lower molecular weight
✓
Answer
Correct option: D.
$H_2Se$ because of lower molecular weight
d
The oxide with the highest positive oxidation state on the element other than $O$ should be most acidic. Oxidation state of $V$ in $V_2O_5$ and $N$ in $N_2O_5$ are $+5$. But the electronegativity of $N$ is higher, making $N_2O_5$ the most acidic oxide.
The oxide with the highest positive oxidation state on the element other than $O$ should be most acidic. Oxidation state of $V$ in $V_2O_5$ and $N$ in $N_2O_5$ are $+5$. But the electronegativity of $N$ is higher, making $N_2O_5$ the most acidic oxide.
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